સંબંધિત સૂત્રો
અન્ત્યયોરેવ
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વિલોકનમ્
“ફક્ત નિરીક્ષણ દ્વારા”
પેટર્ન ઓળખ અને દૃશ્ય ગણતરી
સિદ્ધાંત
Instant Divisibility Checks
You can tell if a number is divisible by 2, 3, 4, 5, 8, 9, or 11 just by looking at its digits!
Divisible by 2
Rule: Last digit is even (0, 2, 4, 6, 8)
- 348 → last digit 8 (even) → YES ✓
- 567 → last digit 7 (odd) → NO ✗
Divisible by 3
Rule: Sum of digits is divisible by 3
- 246 → 2+4+6 = 12 → 12÷3 = 4 → YES ✓
- 457 → 4+5+7 = 16 → 16÷3 has remainder → NO ✗
Divisible by 4
Rule: Last TWO digits form a number divisible by 4
- 1236 → last two: 36 → 36÷4 = 9 → YES ✓
- 3418 → last two: 18 → 18÷4 has remainder → NO ✗
- Quick check: if tens digit is even, ones must be 0, 4, or 8
- If tens digit is odd, ones must be 2 or 6
Divisible by 5
Rule: Last digit is 0 or 5
- 385 → last digit 5 → YES ✓
- 2470 → last digit 0 → YES ✓
- 892 → last digit 2 → NO ✗
Divisible by 8
Rule: Last THREE digits form a number divisible by 8
- 12416 → last three: 416 → 416÷8 = 52 → YES ✓
- 5123 → last three: 123 → not divisible by 8 → NO ✗
Divisible by 9
Rule: Sum of digits is divisible by 9
- 4563 → 4+5+6+3 = 18 → 18÷9 = 2 → YES ✓
- 1234 → 1+2+3+4 = 10 → not divisible by 9 → NO ✗
Divisible by 11
Rule: Alternating sum of digits is 0 or divisible by 11
Start from right, alternately add and subtract:
- 1331 → 1 - 3 + 3 - 1 = 0 → YES ✓
- 2728 → 8 - 2 + 7 - 2 = 11 → YES ✓
- 1234 → 4 - 3 + 2 - 1 = 2 → NO ✗
Why These Work
Powers of 10 Pattern:
- 10 ≡ 0 (mod 2, 5)
- 100 ≡ 0 (mod 4)
- 1000 ≡ 0 (mod 8)
- 10 ≡ 1 (mod 3, 9) → digit sum works
- 10 ≡ -1 (mod 11) → alternating sum works
Quick Reference Table
| Divisor | Test |
|---|---|
| 2 | Last digit even |
| 3 | Sum of digits ÷ 3 |
| 4 | Last 2 digits ÷ 4 |
| 5 | Last digit 0 or 5 |
| 6 | Divisible by both 2 AND 3 |
| 8 | Last 3 digits ÷ 8 |
| 9 | Sum of digits ÷ 9 |
| 10 | Last digit is 0 |
| 11 | Alternating digit sum |
પગલાં
Identify which divisor you're testing
Testing divisibility by 3
Apply the appropriate rule for that divisor
For 3: add all the digits
Check if the result meets the criterion
Is the sum divisible by 3?
Conclude YES or NO
If yes → number is divisible by 3
ઉદાહરણો
Is 5,268 divisible by 4?
સરળFor 4, check last 2 digits
Last 2 digits: 68
Is 68 divisible by 4?
68 ÷ 4 = 17
Conclusion
YES, 5,268 is divisible by 4
જવાબ: Yes
Is 8,372 divisible by 3?
સરળFor 3, sum the digits
8 + 3 + 7 + 2 = 20
Is 20 divisible by 3?
20 ÷ 3 = 6 remainder 2
Conclusion
NO, 8,372 is not divisible by 3
જવાબ: No
Is 7,326 divisible by 9?
મધ્યમFor 9, sum the digits
7 + 3 + 2 + 6 = 18
Is 18 divisible by 9?
18 ÷ 9 = 2 ✓
Conclusion
YES, 7,326 is divisible by 9
Verify
7,326 ÷ 9 = 814
જવાબ: Yes
Is 2,937 divisible by 11?
મુશ્કેલFor 11, use alternating sum (right to left)
7 - 3 + 9 - 2 = 11
Is result 0 or multiple of 11?
11 is a multiple of 11 ✓
Conclusion
YES, 2,937 is divisible by 11
Verify
2,937 ÷ 11 = 267
જવાબ: Yes
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